Question #120417
Obtain the 6th root of (-7)
1
Expert's answer
2020-06-08T16:56:36-0400

7=7(1+0i)=7eiπ-7=7(-1+0*i)=7e^{i\pi}

7eiπ6=76eiπ+2πk6,k=0..5\sqrt[6]{7e^{i\pi}}=\sqrt[6]{7}e^{i\frac{\pi+2\pi k}{6}},k=0..5


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