Question #116083
9.The principal value of the argument of (1+ ˆš3)(1−i) is____
\\(-5\\fra{\\pi}{12}\\)
\\(\\fra{5\\pi}{12}\\)
\\(\\fra{-\\pi}{12}\\)
\\(\\fra{\\pi}{12}\\)
1
Expert's answer
2020-05-24T17:55:09-0400
Arg((1+i3)(1i))=Arg(1+i3)+Arg(1i)=Arg((1+i\sqrt{3})(1-i))=Arg(1+i\sqrt{3})+Arg(1-i)=

=π3+(π4)=π12={\pi\over 3}+(-{\pi\over 4})={\pi\over 12}


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