the figures 4,5,6,7,8 are written in every possible order.the number of numbers greater than 56000 is        
        1
                    
                            
                                        2012-04-10T07:19:10-0400
                    
                                                    
                                First, let's find all the combinations:
   5! = 120.
Since the formula is
n(n-1)(n-2)(n-3)...(n-r),
where r is
   (the number of positions)-1,
so now we see: combinations which don't accept 4's at the start and 54's
   4! = 24
   3! = 6
   24+6 = 30
and we have:
   120-30 = 90.                            
                                                 
                 
                    
        
            
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