Question #50144

3 buses have to cross a long bridge, and it is so narrow that a bus cannot overtake another. The buses can
have only integer-number-velocities ranging from 10ms-1
to 20ms-1
and no two buses can have the same
speed. How many ways the velocities can be distributed among the buses so that they can cross the
bridge without any accident?
1

Expert's answer

2014-12-26T09:48:39-0500

Answer on Question #50144 – Math – Combinatorics | Number Theory

3 buses have to cross a long bridge, and it is so narrow that a bus cannot overtake another. The buses can have only integer-number-velocities ranging from 10ms110\mathrm{ms}^{-1} to 20ms120\mathrm{ms}^{-1} and no two buses can have the same speed. How many ways the velocities can be distributed among the buses so that they can cross the bridge without any accident?

Solution:

We can choose integer values from 10ms110\mathrm{ms}^{-1} to 20ms120\mathrm{ms}^{-1}, hence the number of velocities is


n=11n = 11


When choosing r=3r = 3 of them we have permutations formula


K=n!(nr)!(r!)=11!(113)!3!=165K = \frac{n!}{(n - r)!(r!)} = \frac{11!}{(11 - 3)! * 3!} = 165


Answer: 165.

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