Question #326602

Prove that if 𝑎|𝑏 and 𝑏≠0, then |𝑎| ≤ |𝑏|.


1
Expert's answer
2022-04-14T04:15:52-0400

abna=bb=na=naSinceb0,n0n{1,1,2,2,...}n1Thenb1a=aa|b\Rightarrow na=b\Rightarrow \left| b \right|=\left| na \right|=\left| n \right|\left| a \right|\\Since\,\,b\ne 0, n\ne 0\Rightarrow n\in \left\{ -1,1,-2,2,... \right\} \Rightarrow \left| n \right|\geqslant 1\\Then\\\left| b \right|\geqslant 1\cdot \left| a \right|=\left| a \right|


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