Solution
Given that
x mod11 =5
Then, for some value of "k", we can write x mod11= 5, as
x=11k+5
Then
x2=(11k+5)(11k+5)
x2=121k2+55k+55k+25
x2=121k2+110k+25
Now,
x2 mod 11=(121k2+110k+25) mod 11
x2 mod 11=121k2 mod 11 + 110k mod 11+ 25 mod 11
x2 mod 11=0 + 0+ 3 because 25=2×11+3
Therefore,
x2 mod 11 =3
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