Question #311702

Prove for all integers and b, if mod 8 = 5 and mod 8 = 3 then ab mod 8 = 7.



Expert's answer

Since amod8=5a \mod 8 = 5 and bmod8=3,b \mod 8 = 3, it follows that abmod8=35mod8=15mod8=7.ab \mod 8 = 3 \cdot 5\mod 8 =15\mod 8 =7.


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