Prove for all integers a and b, if a mod 8 = 5 and b mod 8 = 3 then ab mod 8 = 7.
Since amod 8=5a \mod 8 = 5amod8=5 and bmod 8=3,b \mod 8 = 3,bmod8=3, it follows that abmod 8=3⋅5mod 8=15mod 8=7.ab \mod 8 = 3 \cdot 5\mod 8 =15\mod 8 =7.abmod8=3⋅5mod8=15mod8=7.
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