Question #279372

Show that among any group of five (not necessarily consecutive) integers, there


are two with the same remainder when divided by 4


Expert's answer

every integer can be expressed as

4k,4k+1,4k+2,4k+34k,4k+1,4k+2,4k+3

where k = 0,1,2,...

so, if we have 5 integers two of them have same remainder


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