Show that among any group of five (not necessarily consecutive) integers, there
are two with the same remainder when divided by 4
every integer can be expressed as
4k,4k+1,4k+2,4k+34k,4k+1,4k+2,4k+34k,4k+1,4k+2,4k+3
where k = 0,1,2,...
so, if we have 5 integers two of them have same remainder
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments