Answer to Question #201175 in Combinatorics | Number Theory for Fatowore Samson

Question

4C2 is equal to _____________

Answer 1

We know that,

$^nC_r=\dfrac{n!}{r!\cdot(n-r)!}$

So,

$^4C_2=\dfrac{4!}{2!\cdot (4-2)!}=\dfrac{4!}{2!\times2!~}=\dfrac{24}{4}=6$

Hence,

$\boxed{^4C_2=6}$