Question #178142

Find the integer a such that a ≡ 08(mod23) and −22 ≤ a ≤ 0. 


1
Expert's answer
2021-04-15T06:57:19-0400

The congruence relation may be rewritten as


a=23k+8,where kintegera=23k+8, where \space k-integer

if


22a0-22\leq a \leq 0

then


2223k+80-22\leq 23k+8 \leq 03023k8-30\leq 23k \leq -8

so

k=1k=-1

and


a=23k+8=23(1)+8=15a=23k+8=23(-1)+8=-15158(mod23) and 22150-15\equiv8(mod 23)\space and \space -22\leq -15 \leq 0

Answer: a=-15


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