Answer to Question #164300 in Combinatorics | Number Theory for Gabriela

Question #164300

If 20% of 90 mice doubled back on their tracks, 40% jumped into mouse holes, and the rest ran through water, how many ran through water?

Expert's answer

90*0.2=18

90-18=72

72*0.4=28.8

the mouse can only be whole, then not 28.8 but 28

90-18-28=44

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