Answer to Question #146446 in Combinatorics | Number Theory for Josh

Question

In how many ways can 4 married couples attending a concert be seated in a row of eight seats if members of same gender must be seated together?
a.756
b.1152
c.576
d.24

Answer 1

There are two groups with 4 members in each. Then

$$2!\times4!\times4!=2\times24\times24=1152$$

b. 1152