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Question #146446
In how many ways can 4 married couples attending a concert be seated in a row of eight seats if members of same gender must be seated together?
a.756
b.1152
c.576
d.24
Expert's answer
There are two groups with 4 members in each. Then
2
!
×
4
!
×
4
!
=
2
×
24
×
24
=
1152
2!\times4!\times4!=2\times24\times24=1152
2
!
×
4
!
×
4
!
=
2
×
24
×
24
=
1152
b. 1152
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