Question #117128

Find an explicit formula for the Fibonacci numbers.

Expert's answer

The explicit form of Fibonacci numbers is given by the Binet formula

Fn=(1+5)n+1(15)n+12n+15,n0F_n=\frac{(1+\sqrt5)^{n+1}-(1-\sqrt5)^{n+1}}{2^{n+1}\sqrt5}, n\geq0 (see the book Alfred Renyi, Dialogues of math., math collection Trilogy, Publishing House Mir, Moscow, 1980, p.311).


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