Solution.
Assume that √5 is a rational number. Suppose there exists a rational number whose square is 5. This number can be given as an unbreakable fraction where are natural numbers.
Then
is divisible by 5, so is divisible by 5. Then is divisible by 25. If so, then is divisible by 5, and therefore is divisible by 5. It turns out that the fraction is short. We came to a contradiction of the original judgment (that the number is rational). Therefore, the number is irrational.
Answer: the number is irrational.
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