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Calculus
Question 1.
∬_D▒〖x cosy dA,〗 D is bounded by y=0 and y=x^2 and x=1
Question 2
∬_D▒〖(x+y)dA,〗 D is bounded by y=√x and y=x^2
Question 3.
∬_D▒〖y^3 dA,〗 D is the triangular region with
vertices (0,2),(1,1) and (3,2)
Question 4.
∬_D▒〖xy^2 dA,〗 D is bounded by x=0 and x=√(1-y^2 )
∬_D▒〖x cosy dA,〗 D is bounded by y=0 and y=x^2 and x=1
Question 2
∬_D▒〖(x+y)dA,〗 D is bounded by y=√x and y=x^2
Question 3.
∬_D▒〖y^3 dA,〗 D is the triangular region with
vertices (0,2),(1,1) and (3,2)
Question 4.
∬_D▒〖xy^2 dA,〗 D is bounded by x=0 and x=√(1-y^2 )
Calculus
I'm fed up with this question from my book. I've calculated the constants to this equation but got stuck at the asymptotes and local extreme values calculations which I need to plot the graph, perhaps anyone could help me out or guide me towards the solution of calculating the asymptotes/local extreme values and then to plot the graph.
Equation:
Define the constants A,B,C so that a function which is defined by
f(x) =
(1) (6/pi) arctan(2-(x+2)²) when x < -1
(2) x + c* |x| - 1 when -1 ≥ x ≥ 1
(3) (1/Ax+B) + 4 when x > 1 och Ax + B ≠ 0
is continuous at x = -1 and differentiable in x = 1
_______________
I calculated the constants, A,B,C to:
A = -18
B = 16
C = 7/2
Any help is appreciated,
Thanks, Michael.
Equation:
Define the constants A,B,C so that a function which is defined by
f(x) =
(1) (6/pi) arctan(2-(x+2)²) when x < -1
(2) x + c* |x| - 1 when -1 ≥ x ≥ 1
(3) (1/Ax+B) + 4 when x > 1 och Ax + B ≠ 0
is continuous at x = -1 and differentiable in x = 1
_______________
I calculated the constants, A,B,C to:
A = -18
B = 16
C = 7/2
Any help is appreciated,
Thanks, Michael.
Calculus
a person has a height of 5 feet 7 1/2 inches and has a weight of 145 1/4 lbs. express his height in cm and weight in kilograms.
Calculus
make a graph of x^2+y^2=1
Calculus
make a graph of w=(y-x^2)^1/2
Calculus
Use differential, (i.e. linear approximation), to approximate cube root(64.3) as follows:
Let f(x)=cube root(x). The linear approximation to f(x) at x=64 can be written in the form y=mx+b. Computer m and b.
m=
b=
Using this, find the approximation for cube root(64.3).
Answer:
Let f(x)=cube root(x). The linear approximation to f(x) at x=64 can be written in the form y=mx+b. Computer m and b.
m=
b=
Using this, find the approximation for cube root(64.3).
Answer:
Calculus
The figure below shows f(x) and its local linearization at x=a, y=5x−3. (The local linearization is shown in blue.)
http://imageshack.us/photo/my-images/13/ob50k849dw032549setassi.png/
What is the value of a? a=
What is the value of f(a)? f(a)=
Use the linearization to approximate the value of f(2.6). f(2.6)=
Is the approximation an under- or overestimate? (Enter under or over.)
http://imageshack.us/photo/my-images/13/ob50k849dw032549setassi.png/
What is the value of a? a=
What is the value of f(a)? f(a)=
Use the linearization to approximate the value of f(2.6). f(2.6)=
Is the approximation an under- or overestimate? (Enter under or over.)
Calculus
Find the degree 3 Taylor polynomial T3(x) of the function f(x)=(−5x+34)3/2 at a=6.
T3(x)=
T3(x)=
Calculus
Write the Taylor polynomial T5(x) for the function f(x)=cos(x) centered at x=0.
Answer: T5(x)=
Answer: T5(x)=
Calculus
Find the Taylor polynomials of degree n approximating
2/(3−3x)
for x near 0:
For n=3, P3(x)=
For n=5, P5(x)=
For n=7, P7(x)=
2/(3−3x)
for x near 0:
For n=3, P3(x)=
For n=5, P5(x)=
For n=7, P7(x)=
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#340153 on Dec 2023
#340153 on Dec 2023