Question

Find the area under the curve y= x*3-6x*2 , the x-axis and the lines x =1 and x=2.

Answer 1

Solution Using the properties of a definite integral, we obtain

$$S=-\int_1^2(x^3-6x^2)dx=(2x^3-\frac {x^4} {4})|_1^2=16-4-2+\frac {1} {4}=\frac{41} {4}$$

Answer

$$\frac{41} {4}$$