Notice that "|g| = 1" for all "t" and "\\pi^2 > 2\\pi"
Then the image of "[0, \\pi]" under "g" is indeed the whole unit circle
We'll notice that "cosh^2t - sinh^2t = 1" for all "t"
So the needed sketch is just a part of the hyperbola "x^2 - y^2 = 1" with endpoints at "(cosh(-2), sinh(-2))\\: and\\: (cosh\\,2,sinh\\,2)"
Both coordinates depend linearly on "t" so the needed sketch will be a line segment with endpoints at "g(0)" and "g(1)"
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