Question #97197
Ascertain that (del)(r^n)=nr^n-2 vector r
1
Expert's answer
2019-10-28T10:44:05-0400

For a function f(r)f(r) , which depends solely on absolute value of radius-vector r\bold r, the formula for the gradient is the following: f(r)=f(r)rrr\nabla f(r) = \frac{\partial f(r)}{\partial r} \frac{\bold r}{r} (this can be shown via direct differentiation w.r.t components or r\bold r). Hence, (rn)=nrn1rr=nrn2r\nabla (r^n) = n r^{n-1} \cdot \frac{\bold r}{r} = n r^{n-2} \bold {r}.


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