Let's find a slant asymptote of this curve
Let's rewrite the equation
"x^3+y^3-3axy=0"
The slant asymptote is "y=mx+c"
Substuting this to the equation will give us
"x^3+(mx+c)^3-3ax(mx+c)=(1+m^2)x^3+(3m^2c+3am)x^2+(3mc^2-3ac)x+c^3=0"
Therefore
"1+m^3=0;\\qquad m=-1"
"3m^2c-3am=0;\\qquad mc-a=0;\\qquad c=-a"
Hence "y=-x-a" is a slant asymptote of this curve
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