Answer to Question #96891 in Calculus for Ojugbele Daniel

Question

A particle P has velocity (3i+j)m/s at a time t=0, The particle moves with constant acceleration a=(2i+3j)m/s square. Find the speed of the particle after 3seconds.

Answer 1

$v(t)=\int(2i+3j)dt=2ti+3tj+C,$

$v(0)=3i+j,\;\;so\;\;C=3i+j$ and

$v(t)=(2t+3)i+(3t+1)j\;\;m/s,$

$v(3)=9i+10j\;\;m/s.$