We need to find the Derivative of g(x) at x= 9.
We know the derivative of ln (x) is 1/x.
So, derivative of ln (f(x) ) is [ 1/f(x)] * derivative of f(x)
Given function g(x) = ln ( ln ( ln (f(x))))
Differentiate with respect to x
g' (x) = ( 1 / ln (ln (f(x))) * (1/ ln (f(x)) * (1 / f(x) ) * f ' (x)
Plug x = 9
g' (9) = ( 1 / ln (ln (f(9))) * (1/ ln (f(9)) * (1 / f(9) ) * f ' (9)
g' (9) = ( 1 / ln (ln (A)) * (1/ ln (A) * (1 / A ) * B
Since f(9) = A and f ' (9 ) = B.
Answer: g' (9) = B / ( A* ln (A) * ln (ln A) ).
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