Question #94763
Differitiate:Y=X^2(X^2+2)^2
1
Expert's answer
2019-09-19T10:09:09-0400

Let us differentiate using:

  1. The Leibniz rule: iff(x)=g1(x)g2(x)...gn(x)f(x) = g_1(x) g_2(x) ... g_n(x), then f(x)=g1g2...gn+...+g1...gnf'(x) = g_1' g_2 ... g_n + ... + g_1 ... g_n'
  2. The chain rule: iff(x)=g(h(x))f(x) = g(h(x)) , then f(x)=g(h(x))h(x)f'(x) = g'(h(x))h'(x)


Hence, y(x)=2x(x2+2)2+x22(x2+2)2x=2(3x5+8x3+4x)y'(x) = 2 x (x^2 + 2)^2 + x^2 \cdot 2 (x^2 + 2) \cdot 2 x = 2 (3 x^5 + 8 x^3 + 4 x).


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