Let us differentiate using:
Hence, y′(x)=2x(x2+2)2+x2⋅2(x2+2)⋅2x=2(3x5+8x3+4x)y'(x) = 2 x (x^2 + 2)^2 + x^2 \cdot 2 (x^2 + 2) \cdot 2 x = 2 (3 x^5 + 8 x^3 + 4 x)y′(x)=2x(x2+2)2+x2⋅2(x2+2)⋅2x=2(3x5+8x3+4x).
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