∫01x4(1−x)3dx=B(5,4)=Γ(5)Γ(4)Γ(9)==4!⋅3!8!=2⋅35⋅6⋅7⋅8=1280\int_{0}^1x^{4}(1-x)^{3}dx=\Beta(5,4)=\frac{\Gamma(5)\Gamma(4)}{\Gamma(9)}=\\ =\frac{4!\cdot 3!}{8!}=\frac{2\cdot3}{5\cdot 6\cdot 7\cdot8}=\frac{1}{280}∫01x4(1−x)3dx=B(5,4)=Γ(9)Γ(5)Γ(4)==8!4!⋅3!=5⋅6⋅7⋅82⋅3=2801
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