Reasoning depends on the reading of the question. In both cases, the limit does not exist:
"\\lim\\limits_{x\\rarr -1-0}\\sqrt{\\frac{x^2+3x+4}{x^3+1}} \\text{does not exist},\\\\\n\\lim\\limits_{x\\rarr -1+0}\\sqrt{\\frac{x^2+3x+4}{x^3+1}}=\\infin,\\\\\n\\lim\\limits_{x\\rarr -1}\\frac{ \\sqrt{x^2+3x+4}}{x^3+1}=\\frac{\\sqrt {2}}{0}=\\infin."
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