Question #91398
Q.Choose the correct answer.
The radius of convergence for power series ∑_(n=1)^∞▒(2^k 〖(x+1)〗^(k+1))/k is
a.3/2
b.1
c.∞
d.½
1
Expert's answer
2019-07-10T13:11:22-0400
uk=2kku_k = \frac{2^k}{k}

R=limkukuk+1=limk2kkk+12k+1=12R=\lim_{k\to \infin}\frac{u_k}{u_{k+1}}=\lim_{k\to \infin}\frac{2^k}{k}\cdot\frac{k+1}{2^{k+1}}=\frac{1}{2}

The correct answer is d) 1/2.


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