Solution. We use the integration formula in parts
"\\int \\frac {ln(x+1)} {\\sqrt{x+1}}dx=\n\\begin{vmatrix}\n u=ln(x+1) & dv=\\frac {dx} {\\sqrt{x+1}} \\\\\n du=\\frac {dx}{x+1} & v=2\\sqrt{x+1}\n\\end{vmatrix}="
"=2\\sqrt{x+1}*ln(x+1)-\\int \\frac{2\\sqrt{x+1}}{x+1}dx="
"=2\\sqrt{x+1}*ln(x+1)-\\int \\frac{2} {\\sqrt{x+1}}dx="
"=2\\sqrt{x+1}*ln(x+1)-4\\sqrt{x+1}+C"where C is constant.
Answer.
"2\\sqrt{x+1}*ln(x+1)-4\\sqrt{x+1}+C" where C is constant.
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