Answer to Question #88316 in Calculus for Shivam Nishad

Question #88316

Evaluate the following integrals:
i) ∫ [1/(1+x²)tan^-1x]dx

Expert's answer

"\\int{\\frac{atan(x)dx}{1+x^2}}=(u=atan(x),\\;du=\\frac{dx}{1+x^2})=\\int{udu}=\\frac{u^2}{2}+C=\\frac{(atan(x))^2}{2}+C"

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