Answer to Question #87993 in Calculus for Joshua

Question

3.Evaluate ∫(3x−2)^6 dx
a.(3x+2)^7
--------- +c
2
b.(3x+2)^7
--------- +c
21

c. (3x-2)^7
--------- +c
21

d.3(3x+2)^7
--------- +c
2

4.Integrate with respect to x :∫3 x
-1 -------dx
√7+x^2
a.2√2
b.4√2
c.4−2√2
d.√2

Answer 1

Task 3.

$$\int(3x-2)^6dx = (1/3)* \int(3x-2)^6d(3x-2)$$

$$=(1/3)*(1/7)*(3x-2)^7 + c,$$

c is an integration constant.

Task 4.

$$\int3x-1dx=(3/2)*x^2-x+c,$$

c is an integration constant.