"2x+2y=20\\:\\;->\\;\\;y=10-x\\\\\nS=xy=x(10-x)\\\\\n\\frac{dS}{dx}=10-2x\\\\\n\\frac{dS}{dx}=0\\;\\;->\\;\\;x=5,\\;\\;y=10-x=5.\\\\\nPoint\\;(5,5)\\;is\\ the\\ maximum\\ point\\ because\\;\\;\\frac{d^2S}{dx^2}=-2<0"
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