Answer to Question #87782 in Calculus for Shivam Nishad

Question

Find the values of x for which the function f(x)=x^3–3x, is increasing

Answer 1

$f(x)\ increases\ when\ f'(x)>0.\\ f'(x)=3x^2-3.\\ 3x^2-3>0\\ x<-1,\;\;or\;\;x>1$