If n=1 , then statement is true. Denote a(n)=2+4+10+...+(4n-2), b(n)=2n^2.
Assume that the statement is true for n : a(n)=b(n). We show that it follows from here that
a(n+1)=b(n+1), a(n)=b(n)→a(n+1)=a(n)+(4n+4-2)=a(n)+4n+2=b(n)+4n+2=
=2n^2+4n+2=2(n+1)^2=b(n+1).The statement is true.
Pay attetion in the left part there are no brackets (4n-2). Without brackets the expression in the
left part is written incorrectly.
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