2019-04-01T11:05:54-04:00
x2−5t−9
4.Evaluate the limit lim x → −∞ ---------
2x^4+3x^3
a.4
b.2
c.0
d.1
5.Given y(x)=x^4−4x^3+3x^2−5x, evaluate d^4y
-----
dx^4
a.30
b.42
c.24
d.22
1
2019-04-03T10:03:10-0400
4. lim x → − ∞ x 2 − 5 x − 9 2 x 4 + 3 x 3 = lim x → − ∞ x 2 / x 4 − 5 x / x 4 − 9 / x 4 2 x 4 / x 4 + 3 x 3 / x 4 = 4.\ \lim\limits_{x\rarr - \infin }{{x^2-5x-9} \over {2x^4+3x^3}}=\lim\limits_{x\rarr - \infin }{{x^2/x^4-5x/x^4-9/x^4} \over {2x^4/x^4+3x^3/x^4}}= 4. x → − ∞ lim 2 x 4 + 3 x 3 x 2 − 5 x − 9 = x → − ∞ lim 2 x 4 / x 4 + 3 x 3 / x 4 x 2 / x 4 − 5 x / x 4 − 9/ x 4 =
= lim x → − ∞ 1 / x 2 − 5 / x 3 − 9 / x 4 2 + 3 / x = 0 + 0 − 0 2 − 0 = 0 =\lim\limits_{x\rarr - \infin }{{1/x^2-5/x^3-9/x^4} \over {2+3/x}}={{0+0-0} \over {2-0}}=0 = x → − ∞ lim 2 + 3/ x 1/ x 2 − 5/ x 3 − 9/ x 4 = 2 − 0 0 + 0 − 0 = 0
c . 0 c. \ 0 c . 0
5. d y d x = 4 x 3 − 12 x 2 + 6 x − 5 5.\ {dy \over dx}=4x^3-12x^2+6x-5 5. d x d y = 4 x 3 − 12 x 2 + 6 x − 5
d 2 y d x 2 = 12 x 2 − 24 x + 6 {d^2y \over dx^2}=12x^2-24x+6 d x 2 d 2 y = 12 x 2 − 24 x + 6
d 3 y d x 3 = 24 x − 24 {d^3y \over dx^3}=24x-24 d x 3 d 3 y = 24 x − 24
d 4 y d x 4 = 24 {d^4y \over dx^4}=24 d x 4 d 4 y = 24
c . 24 c. \ 24 c . 24
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