Question #86719
Find the rates of convergence of the following functions as h → 0.
lim
h→0
sin (h − h cos h) /h
= 0
1
Expert's answer
2019-03-21T10:08:32-0400
limh0sin(hhcos(h))h\lim_{h\to0} \frac{sin(h-hcos(h))}{h}

So, we know that


limh0sin(h)h=1\lim_{h\to0} \frac{sin(h)}{h}=1

Let's multiply the numerator and denominator by (h-hcos(h)):


limh0sin(hhcos(h))(hhcos(h))h(hhcos(h))=(1)\lim_{h\to0} \frac{sin(h-hcos(h))*(h-hcos(h))}{h*(h-hcos(h))} = (1)limh0sin(hhcos(h))hhcos(h)=1\lim_{h\to0}\frac{sin(h-hcos(h))}{h-hcos(h)}=1

(1)=limh0hhcos(h)h=limh01cos(h)(1) = \lim_{h\to0} \frac{h-hcos(h)}{h}=\lim_{h\to0}1-cos(h)

Use the Maclaurin series for cosine:


cos(h)=1h22!+h44!h66!+...cos(h) = 1-\frac{h^{2}}{2!}+\frac{h^{4}}{4!}-\frac{h^{6}}{6!}+...

1cos(h)=1(1h22!+...)=h22+...=O(h2)1-cos(h)=1-(1-\frac{h^{2}}{2!}+...)=\frac{h^{2}}{2}+...=O(h^{2})

Answer: the function has quadratic convergence.





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