So, we know that
Let's multiply the numerator and denominator by (h-hcos(h)):
"(1) = \\lim_{h\\to0} \\frac{h-hcos(h)}{h}=\\lim_{h\\to0}1-cos(h)"
Use the Maclaurin series for cosine:
"1-cos(h)=1-(1-\\frac{h^{2}}{2!}+...)=\\frac{h^{2}}{2}+...=O(h^{2})"
Answer: the function has quadratic convergence.
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