Question #85735
When is f: D ⊂ Rn → Rn called locally invertible? Is the function F given by
F(x+y+z , x − 2y + 3z, x + y −1) locally invertible at (0,1,2)?
Justify your answer.
1
Expert's answer
2019-03-07T10:31:53-0500

Defenition: ff is locally invertible at x0\vec{x}_0 if there is a ϵ>0\epsilon>0 and a function g ⁣:Bϵ(f(x0))Rng\colon B_{\epsilon} (f (\vec{x}_0)) \to \mathbb{R}^n such that


fg(y)=yyBϵ(f(x0))f\circ g (\vec{y}) = \vec{y} \quad \forall \vec{y} \in B_{\epsilon} (f (\vec{x}_0))gf(x)=xxBϵ(x0)g\circ f (\vec{x}) = \vec{x} \quad \forall \vec{x} \in B_{\epsilon} (\vec{x}_0)

Local invertibility refers to whether the closest affine approximation to ff at a given point x0\vec{x}_0 is invertible. The closest affine approximation to ff at a point x0\vec{x}_0 is given by f(x0)f(\vec{x}_0) plus the derivative of ff , otherwise known as the Jacobian in this case.


J(x,y,z)=det(111121130)=3J(x,y,z)=\det \begin{pmatrix} 1 & 1 & 1 \\ 1 & -2 & 1 \\ 1 & 3 & 0 \end{pmatrix} =3

So, FF is locally invertible at any point.


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