c)hence, state the values of x at which the curve possesses stationary points. (note not required to evaluate corresponding y values)
d)determine the nature of the stationary points of the curve.
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Expert's answer
2012-04-24T08:24:59-0400
given the curve y= 1/3 x³ - 9x - 7 & a) evaluate dy/dx
dy/dx = (1/3)*3 x² - 9 - 0 = x² - 9.
b)for what values of x is dy/dx = 0
x² - 9 = 0 (x-3)(x+3) = 0
x = ±3 - zeros of dy/dx. & c)hence, state the values of x at which the curve possesses stationary points. (note not required to evaluate corresponding y values)
x = ±3 - stationary points. & d)determine the nature of the stationary points of the curve.
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