Where does the periodic function f(x) = 2e[sup](sin x/2)[/sup] take on its extreme values andwhat are these values?&
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Expert's answer
2010-10-21T12:22:09-0400
To find extreme points we have to solve the equation: f'(x) = 0.
f'(x) =( 2esin(x/2) )'= 2 sin (x/2) esin(x/2) * 1/2 cos (x/2) = 1/2 sin(x) esin(x/2) = 0; As esin(x/2) is always greater than 0, we can solve the equation only for sin(x) :
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