1.
sin(5x+4y)+x cos(5x+4y)*(5+4y')=y'cos x-ysin x
now you need to find expression for y' from above equation
2.
let's denote theta=t
2/7*t^(2/7-1)+2/7*r^(2/7-1)*r'=0
whence r'=-t^(-5/7)/r^(-5/7)
You can find more info about implicit differentiation
here
Comments
Leave a comment