A. At x->0 sin(π/x) has no limit, but it keeps oscillating from -1 to +1 and back, so it's values are limited [-1,1] lim_(x->0) √(x^2+x^4) = 0 the product of 0 and limited function would be equal to zero.
B. The function sin^2(pi/x) is limited in the domain [0,1], so (1+ sin^2(pi/x)) has the values from 1 to 2. lim_(x->0) √(x) = 0; the product of 0 and the limited function would be equal to zero
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