Question #74724

A jogger runs from her home to a point A, which is 6 km away. For there 6 km, shebegins by running at a constant speed till she reaches a hilly portion 2 km from herhome. Here her speed slows down while she runs up the hill, which is a 1-km run.Then she speeds up while running down the hill.The last 2 km of the run are again atconstant speed. Draw a graph to show the jogger’s speed as a function of the distancefrom her home. Also find the range of this function.
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Expert's answer

2018-03-19T09:01:07-0400

Answer to Question #74724, Math / Calculus

A jogger runs from her home to a point A, which is 6km6 \, \text{km} away. For there 6km6 \, \text{km} , she begins by running at a constant speed till she reaches a hilly portion 2km2 \, \text{km} from her home. Here her speed slows down while she runs up the hill, which is a 1km1 \, \text{km} run. Then she speeds up while running down the hill. The last 2km2 \, \text{km} of the run are again at constant speed. Draw a graph to show the jogger's speed as a function of the distance from her home. Also find the range of this function.

Solution.

Let V1V_{1} is jogger speed at the distance from home to the hill, V2V_{2} is jogger speed at the distance from the hill to the point A, VminV_{\min} is jogger speed at the peak of the hill.

Then we have two cases.

The first case V1>V2V_{1} > V_{2} :



The second case V1<V2V_{1} < V_{2} :



The range of V(s):VminV(s)max(V1,V2)V(s):V_{min}\leq V(s)\leq \max (V_1,V_2)

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