Question

what is the length of the conjugate axis? (y-2)^2/16-(x+1)^2/144=1

Answer 1

Answer on Question #71350, Math / Calculus

What is the length of the conjugate axis?

$$\frac {(y - 2) ^ {2}}{16} - \frac {(x + 1) ^ {2}}{144} = 1$$

Solution

The general equation for vertical hyperbola

$$\frac {(y - k) ^ {2}}{a ^ {2}} - \frac {(x - h) ^ {2}}{b ^ {2}} = 1$$

The conjugate axis of vertical hyperbola is $y = k$.

Length of conjugate axis $= 2b$.

We have that $k = 2, h = -1, a = 4, b = 12$.

Length of conjugate axis $= 2b = 2(12) = 24$.

Answer: Length of conjugate axis $= 24$.

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