Answer to Question #66155 in Calculus for Manoj

Question

Solve the following DEs (I) (dy/dx-1)^2(d^2y/dx^2 +1)^2 y = sin^2(x/2)+x. (2) 2x^2y(d^2y/dx^2)+4y^2= x^2(dy/dx)^2 + 2xy(dy/dx).

Answer 1

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