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Answer to Question #58169 in Calculus for Alexander
Question #58169
Assume f(x)is a function differentiable at the points 0 and 1 with
f(0)=-2, f′(0)=-1, f(1)=1 and f′(1)=0,
and assume F(x)=f(sin(x)).
Compute
f'(0)=
f'(pi/2)=
f(0)=-2, f′(0)=-1, f(1)=1 and f′(1)=0,
and assume F(x)=f(sin(x)).
Compute
f'(0)=
f'(pi/2)=
Expert's answer
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