Answer to Question #58169 in Calculus for Alexander

Question

Assume f(x)is a function differentiable at the points 0 and 1 with
f(0)=-2, f′(0)=-1, f(1)=1 and f′(1)=0,
and assume F(x)=f(sin(x)).

Compute
f'(0)=
f'(pi/2)=