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Answer to Question #56624 in Calculus for Oliver Swanick
Question #56624
7: What is the maximum number of relative extrema contained in the graph of this function?
f(x) = 3x^5 – x^3 + 4x – 2
Answer:______
8: In which direction does the left side of the graph of this function point?
f(x) = 3x^3 – x^2 + 4x – 2
Answer:_______
9: In which direction does the right side of this graph point?
f(x) = 3x^3 – x^2 + 4x – 2
Answer:_______
f(x) = 3x^5 – x^3 + 4x – 2
Answer:______
8: In which direction does the left side of the graph of this function point?
f(x) = 3x^3 – x^2 + 4x – 2
Answer:_______
9: In which direction does the right side of this graph point?
f(x) = 3x^3 – x^2 + 4x – 2
Answer:_______
Expert's answer
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Comments
Dear tatiana. Thank you for correcting us. Since the first derivative is not equal to 0 for all real arguments, the number of relative extremas in Problem 7 is 0. The maximum possible number of relative extrema can be a minimum of 0 up to a maximum of 5-1=4.
the answer for number 7 is wrong. the answer is 4. the answer for the maximum number of relative extremas is always the degree - 1. I got it wrong on an assignment because of this :(
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