Question #5327

Find the most general antiderivative of the function and check your answer by differentiation. f(x)=3*(e^x)+7*(sec^2)(x)

Expert's answer

Indefinite integrals:


(3ex+7sec2(x))dx=3ex+7tan(x)+constant\int \left(3 e ^ {x} + 7 \sec^ {2} (x)\right) d x = 3 e ^ {x} + 7 \tan (x) + \text{constant}


Possible intermediate steps:


(3ex+7sec2(x))dx\int \left(3 e ^ {x} + 7 \sec^ {2} (x)\right) d x


Integrate the sum term by term and factor out constants:


=3exdx+7sec2(x)dx= 3 \int e ^ {x} d x + 7 \int \sec^ {2} (x) d x


The integral of sec2(x)\sec^2 (x) is tan(x)\tan (x):


=7tan(x)+3exdx= 7 \tan (x) + 3 \int e ^ {x} d x


The integral of exe^x is exe^x:


=3ex+7tan(x)+constant= 3 e ^ {x} + 7 \tan (x) + \text{constant}


Check:

Derivative:


ddx(3ex+7tan(x))=3ex+7sec2(x)\frac {d}{d x} \left(3 e ^ {x} + 7 \tan (x)\right) = 3 e ^ {x} + 7 \sec^ {2} (x)


Possible derivation:


ddx(3ex+7tan(x))\frac {d}{d x} \left(3 e ^ {x} + 7 \tan (x)\right)


Differentiate the sum term by term and factor out constants:


=3(ddx(ex))+7(ddx(tan(x)))= 3 \left(\frac {d}{d x} \left(e ^ {x}\right)\right) + 7 \left(\frac {d}{d x} (\tan (x))\right)


The derivative of exe^x is exe^x:


=7(ddx(tan(x)))+3ex= 7 \left(\frac {d}{d x} (\tan (x))\right) + 3 e ^ {x}


The derivative of tan(x)\tan (x) is sec2(x)\sec^2 (x):


=3ex+7sec2(x)= 3 e ^ {x} + 7 \sec^ {2} (x)
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