The volume will be given by
"\\iint\\limits_Df(x,y)dA"
Here D is the triangle, formed by y = x, y = 1, and the y-axis. "z=f(x,y)=1-y"
Hence
"\\iint\\limits_Df(x,y)dA=\\int\\limits_0^1dy\\int\\limits_0^y(1-y)dx=\\int\\limits_0^1y(1-y)dy=\\left(\\frac{y^2}{2}-\\frac{y^3}{3}\\right)_0^1=\\frac{1}{2}-\\frac{1}{3}=\\frac{1}{6}"
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