Answer to Question #43012 in Calculus for shasha
State how many imaginary and real zeros the function has.
f(x) = x4 - 15x2 - 16
4 imaginary; 0 real
3 imaginary; 1 real
2 imaginary; 2 real
0 imaginary; 4 real
Help me please and show work
1
2014-06-03T05:46:01-0400
Assume that y=x^2. We obtain y^2-15y-16=(y-16)(y+1). So, x^2=16 and x^2=-1.
Thus, zeros are 4,-4,i and -i.
And the answer is 2 imaginary; 2 real.
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