Answer to Question #4169 in Calculus for Terence

Question

Determine the relative extrema of the function h = x[sup]2[/sup] + (y - 3)[sup]2[/sup] + (z + 1)[sup]2[/sup]

Answer 1

relative extrema: dh/dx=2x=0
=> x=0 is extremum point
dh/dy=2(y-3)=0
=> y=3 is extremum point
dh/dz=2(z+1)=0
=> z=-1 is extremum point
Hence (0,3,-1) is the relative extrema point of this function