Question #36888

Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative.)
f ''(x) = 8 + x3 + x5
1

Expert's answer

2013-11-15T12:22:43-0500

Task

Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative.)


f(x)=8+x3+x5f''(x) = 8 + x^3 + x^5

Solution

Find f(x)f'(x):


f(x)=(8+x3+x5)dx=8dx+x3dx+x5dx=8x+x44+x66+Cf'(x) = \int \left(8 + x^3 + x^5\right) dx = \int 8dx + \int x^3 dx + \int x^5 dx = 8x + \frac{x^4}{4} + \frac{x^6}{6} + C


Find f(x)f(x):


f(x)=f(x)dx=(8x+x44+x66+C)dx=8xdx+x44dx+x66dx+Cdx=8x22+x54×5+x76×7+Cx+D=4x2+x54×5+x76×7+Cx+D\begin{aligned} f(x) &= \int f'(x) dx = \int \left(8x + \frac{x^4}{4} + \frac{x^6}{6} + C\right) dx = \int 8x dx + \int \frac{x^4}{4} dx + \int \frac{x^6}{6} dx + \int C dx \\ &= 8\frac{x^2}{2} + \frac{x^5}{4 \times 5} + \frac{x^7}{6 \times 7} + Cx + D = 4x^2 + \frac{x^5}{4 \times 5} + \frac{x^7}{6 \times 7} + Cx + D \end{aligned}

Answer

f(x)=4x2+x520+x742+Cx+Df(x) = 4x^2 + \frac{x^5}{20} + \frac{x^7}{42} + Cx + D

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