Question #350410

Find implicit differentiation of 2y+cot(xy^2)=3xy

Expert's answer

"y'(x)=-\\frac{F'_x}{F'_y}=-\\frac{-\\frac{y^2}{\\sin^2(xy^2)}-3y}{2-\\frac{2xy}{\\sin^2(xy^2)}-3x}"

"y'(x)=\\frac{y^2+3y\\sin^2(xy^2)}{2\\sin^2(xy^2)-2xy-3x\\sin^2(xy^2)}"

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