Question #347329

If Φ (r)= 2^r, show that Φ (r+1) =2 Φ(r).

1
Expert's answer
2022-06-06T13:28:56-0400

Φ(r)=2r,Φ (r)= 2^r,

then Φ(r+1)=2r+1=2r21=22r=2Φ(r),\Phi(r+1)=2^{r+1}=2^r\cdot2^1=2\cdot2^r=2\Phi(r),

so the statement Φ(r+1)=2Φ(r)Φ (r+1) =2 Φ(r) holds.


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