If Φ (r)= 2^r, show that Φ (r+1) =2 Φ(r).
"\u03a6 (r)= 2^r,"
then "\\Phi(r+1)=2^{r+1}=2^r\\cdot2^1=2\\cdot2^r=2\\Phi(r),"
so the statement "\u03a6 (r+1) =2 \u03a6(r)" holds.
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